y=16y^2+8y

Solution for y=16y^2+8y equation:

y=16y^2+8y

We move all terms to the left:

y-(16y^2+8y)=0

We get rid of parentheses

-16y^2+y-8y=0

We add all the numbers together, and all the variables

-16y^2-7y=0

a = -16; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-16)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-16}=\frac{0}{-32}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-16}=\frac{14}{-32}
=-7/16
$